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Answer:
(i) Here, I = Rs 2356.25 R =7 \frac{1}{4} \% \text { p.a } = 29 / 4 % p.a. T = 2 \frac{1}{2} \text { years } = 5 / 2 years Hence, P = (I × 100) / (R × T) = Rs (2356.25 × 100) / (29 / 4) × (5 / 2) On further calculation, we get, = Rs (2356.25 × 100 × 4 × 2) / (29 × 5) = Rs (235625 × 8) / (29 × 5) We get, = Rs (47125 × 8) / 29 = Rs 1625 × 8 = Rs 13000 (ii) Amount (A) = Rs 11300 Rate (R) = 4% p.a. Time (T) = 3 years 3 months =3 \frac{3}{12} \text { years } =\frac{3}{4} \text { years } = 13 / 4 years Let the principal be Rs x Hence, S.I. = (P × R × T) / 100 = Rs (x × 4 × 13) / (100 × 4) We get, = Rs 13x / 100 Then, Amount = Principal + Simple Interest = Rs x + Rs 13x / 100 = Rs (x + 13x) / 100 We get, = Rs (100x + 13x) / 100 = Rs (113x / 100) But, the amount given is Rs 11300 Hence, 113x / 100 = 11300 x = 11300 × 100 / 113 x = 100 × 100 We get, x = 10000 Therefore, principal (P) = Rs 10000
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