Find the least number which when divided by 8 15 and 24 leaves remainder 5 in each case

To do: find the least number which when divided by615 and 18 leaves Remainder 5 in each case

Solution:

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.

L.C.M. of 6, 5 and 18 

6 = 2$\times$3

15 = 3$\times$5

18 = 2$\times$3$\times$3

L.C.M. of 6, 15 and 18 = 2$\times$3$\times$3$\times$5

                                         = 90

Now, 

5 $+$ 90 = 95

Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

Question 5 Exercise 3.7

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Answer:

SOLUTION:

Find the lcm of 6, 15 and 18

the lcm of 6, 15 and 18 =2\times3\times3\times5\ =90\

LCM + REMAINDER = 90+5=95

Hence, the required number is 95.

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