To do: find the least number which when divided by615 and 18 leaves Remainder 5 in each case
Solution:
To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.
L.C.M. of 6, 5 and 18
6 = 2$\times$3
15 = 3$\times$5
18 = 2$\times$3$\times$3
L.C.M. of 6, 15 and 18 = 2$\times$3$\times$3$\times$5
= 90
Now,
5 $+$ 90 = 95
Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.
Question 5 Exercise 3.7
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Answer:
SOLUTION:
Find the lcm of 6, 15 and 18
the lcm of 6, 15 and 18 =2\times3\times3\times5\ =90\
LCM + REMAINDER = 90+5=95
Hence, the required number is 95.
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