How many different ways can the letters of the word money be arranged so that the vowels always come together?

In how many different ways can the letters of the word 'JUDGE' be arranged in such a way that the vowels always come together?

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Answer & Explanation

Answer: Option C

Explanation:

In the word 'MATHEMATICS' we treat the vowels AEAI as one letter.

Thus, we have MTHMTCS (AEAI).

Now, we have to arrange 8 letters, out of which M occurs twice, T occurs twice and the rest are different.

Number of ways of arranging these letters = $$\frac{8 !}{(2 !) (2 !)}$$ = 10080.

Now, AEAI has 4 Letters in which A occurs 2 times and the rest are different.

Number of ways of arranging these letters = $$\frac{4 !}{2 !}$$ = 12.

$$\therefore$$ Required number of words = (10080 * 12) = 120960.

Solution:

The word ‘STRANGE’ has seven letters, including two vowels (A,E) and five consonants (S,T,R,N,G).

(i) the vowels come together?

If we consider two vowels to be one letter, we’ll end up with six letters that can be ordered in six different ways.

(A,E) can be combined in 2P2 ways.

As a result, the needed word count is

Using the formula, we can

$ P\text{ }\left( n,\text{ }r \right)\text{ }=\text{ }n!/\left( n-r \right)! $

$ P\text{ }\left( 6,\text{ }6 \right)\text{ }\times \text{ }P\text{ }\left( 2,\text{ }2 \right)\text{ }=\text{ }6!/\left( 6-6 \right)!\text{ }\times \text{ }2!/\left( 2-2 \right)! $

$ =\text{ }6!\text{ }\times \text{ }2! $

$ =\text{ }6\text{ }\times \text{ }5\text{ }\times \text{ }4\text{ }\times \text{ }3\text{ }\times \text{ }2\text{ }\times \text{ }1\text{ }\times \text{ }2\text{ }\times \text{ }1 $

$ =\text{ }720\text{ }\times \text{ }2 $

$ =\text{ }1440 $

(ii) the vowels never come together?

The total number of letters in the word ‘STRANGE’ is given by:

7P7 = 7! = 7 × 6 × 5 × 4 × 3 × 2 × 1

7P7 = 5040

So,

Total number of words where vowels aren’t together = total number of words – total number of words in which vowels are always together

= 5040 – 1440 = 3600

As a result, there are 3600 configurations in which vowels never come together.

Exercise :: Permutation and Combination - General Questions

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13. 

In how many different ways can the letters of the word 'MATHEMATICS' be arranged so that the vowels always come together?

A. 10080
B. 4989600
C. 120960
D. None of these

Answer: Option C

Explanation:

In the word 'MATHEMATICS', we treat the vowels AEAI as one letter.

Thus, we have MTHMTCS (AEAI).

Now, we have to arrange 8 letters, out of which M occurs twice, T occurs twice and the rest are different.

How many different ways can the letters of the word money be arranged so that the vowels always come together?
Number of ways of arranging these letters =
8! = 10080.
(2!)(2!)

Now, AEAI has 4 letters in which A occurs 2 times and the rest are different.

Number of ways of arranging these letters = 4! = 12.
2!

How many different ways can the letters of the word money be arranged so that the vowels always come together?
Required number of words = (10080 x 12) = 120960.


Page 2

Exercise :: Permutation and Combination - General Questions

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7. 

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

Answer: Option D

Explanation:

Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.

The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.

The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.

How many different ways can the letters of the word money be arranged so that the vowels always come together?
Required number of numbers = (1 x 5 x 4) = 20.

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