In how many ways can a music store display four of their 10 best selling records?

Think about it like positions of a sports team. You have 10 players that you need to rearrange for your roster. You can repeat any of the players (or songs). So for position 1 (song 1) you have 10 choices because you haven't picked any to use yet. For spot 2, you already used one player (1 song) so you have 9 left to choose from. Keep going to slot 3, there are 8 remaining, then 7, 6, 5, 4, 3, 2, 1. this is also called FACTORIAL, or written at 10!. To find the answer you would multiply 10*9*8*7...*2*1.  The reason you can do this is because you don't have any restrictions on what song goes in what place, but you also don't want to repeat any of the songs.

I hope that helped. Any other questions feel free to ask.

Brittany...This would be a permutation problem. 10 things taken 10 at a time.

The answer would be 10! That is 10 factorial which is 10*9*8*7*6*5*4*3*2*1 = 3,628,800

10*9*8*7*6*5*4*3*2*1=3,628,800

this is called a permutation, an arrangement of objects(songs) in a specific order

for example, if you have songs A,B, and C you have:

ABC,ACB,BAC,BCA,CAB, and CBA

3 factorial =3 !=3*2*1=6 permutations

Another great question...

The equation for this would be...

10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

3628800 possible arrangements.

first selection, there are 10 to choose from...

second selection, there are 9 to choose from...

third selection, there are 8 to choose from...