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Southern Illinois University Carbondale
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Write an equation for HCO3- acting as an acid: HCOz" + Hzo <-> HzCO3 + OH- CO3 +H2o <-> HCOz- + OH- HCO3- <7> H+ + CO32- HCO:- +At <-7 HzCO3
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Video Transcript
And in this problem we have to write an equation for bicarbonate ion a c o 3 minus acting as an acid. Now, water, bronsted lowry, acid and water bronsted lowry basis, bronsted lowry acids are proton, donar and bronsted lowry basis are proton acceptors here, a co 3 minus acting as an acid. That means in the reaction by carbonate ion donate sub proton. So the equation for a c o 3 minus when it is acting as an acid, will be 8 c, 03 minus a donate. The proton and produces c 032 minus since a c 3 minus donating a proton. So it is acting as an acid or we can write this 1 as a c 03 minus here, 8 plus plus c 032 minus- and this is the third option. Option c is the correct option.