What is the equation of the line which passes through the point 2 3 and (

Solution:

As stated in the problem the line is horizontal. This means that its slope is zero. 

Mathematically it means that it is a line parallel to the x-axis and passing through y = -3 as shown below as horizontal line 1.

What is the equation of the line which passes through the point 2 3 and (

The horizontal line 1 passing through the point (2, -3) is represented by the equation y = -3. 

There is another horizontal line 2 which is passing through the point (1,2) which also has slope zero as it is parallel to the x-axis and represented by the equation y = 2


What is the equation of the horizontal line that passes through the point (2, -3)?

Summary:

The equation of the horizontal line that passes through the point (2, -3) is y = -3

Explanation:

Begin by finding the slope of the line using the formula

#m = (y_2-y_1)/(x_2-x_1)#

For the points
#(2,-3) and (1,-3)#

#x_1 = 2#
#x_2 = -3#
#x_2 = 1#
#y_2=-3#

#m = (-3-(-3))/(1-2)#

#m=0/-1#

#m=0#

This equation is actually a horizontal line running through the y axis at #y=-3#

Solution : Let the equation of straight line be `(x)/(a)+(y)/(b)=1`. <br> It passes through the point `(2,3)` <br> `(2)/(a)+(3)/(b)=1`…..`(1)` <br> Given that `a+b=10` <br> `implies b=10-a` <br> From eq. `(1)` <br> `(2)/(a)+(3)/(10-a)=1` <br> `implies (20-2a+3a)/(a(10-a))=1` <br> `implies20+a=10a-a^(2)` <br> `implies a^(2)-9a+20=0` <br> `implies (a-4)(a-5)=0` <br> `implies a=4` or `a=5` <br> If `a=4` then `b=10-4=6` <br> If `a=5` then `b=10-5=5` <br> Therefore, equation of line is <br> `(x)/(4)+(y)/(6)=1` or `(x)/(5)+(y)/(5)=1` <br> `implies 3x+2y=12` or `x+y=5`

First, let's see it in action. Here are two points (you can drag them) and the equation of the line through them. Explanations follow.

../geometry/images/geom-line-equn.js

The Points

We use Cartesian Coordinates to mark a point on a graph by how far along and how far up it is:


Example: The point (12,5) is 12 units along, and 5 units up

Steps

There are 3 steps to find the Equation of the Straight Line :

  • 1. Find the slope of the line
  • 2. Put the slope and one point into the "Point-Slope Formula"
  • 3. Simplify

Step 1: Find the Slope (or Gradient) from 2 Points

What is the slope (or gradient) of this line?

What is the equation of the line which passes through the point 2 3 and (

We know two points:

  • point "A" is (6,4) (at x is 6, y is 4)
  • point "B" is (2,3) (at x is 2, y is 3)

The slope is the change in height divided by the change in horizontal distance.

Looking at this diagram ...

What is the equation of the line which passes through the point 2 3 and (

Slope m  =  change in ychange in x  =  yA − yBxA − xB

In other words, we:

  • subtract the Y values,
  • subtract the X values
  • then divide

Like this:

m  =   change in y change in x  =   4−3 6−2  =   1 4 = 0.25

It doesn't matter which point comes first, it still works out the same. Try swapping the points:

m  =   change in y change in x  =   3−4 2−6  =   −1 −4 = 0.25

Same answer.

Step 2: The "Point-Slope Formula"

Now put that slope and one point into the "Point-Slope Formula"

What is the equation of the line which passes through the point 2 3 and (

Start with the "point-slope" formula (x1 and y1 are the coordinates of a point on the line):

y − y1 = m(x − x1)

We can choose any point on the line for x1 and y1, so let's just use point (2,3):

y − 3 = m(x − 2)

We already calculated the slope "m":

m = change in ychange in x = 4−36−2 = 14

And we have:

y − 3 = 14(x − 2)

That is an answer, but we can simplify it further.

Step 3: Simplify

Start with:y − 3 = 14(x − 2)

Multiply 14 by (x−2):y − 3 = x424

Add 3 to both sides:y = x424 + 3

Simplify:y = x4 + 52

And we get:

y = x4 + 52

Which is now in the Slope-Intercept (y = mx + b) form.

Check It!

Let us confirm by testing with the second point (6,4):

y = x/4 + 5/2 = 6/4 + 2.5 = 1.5 + 2.5 = 4

Yes, when x=6 then y=4, so it works!

Another Example

Example: What is the equation of this line?

What is the equation of the line which passes through the point 2 3 and (

Start with the "point-slope" formula:

y − y1 = m(x − x1)

Put in these values:

  • x1 = 1
  • y1 = 6
  • m = (2−6)/(3−1) = −4/2 = −2

And we get:

y − 6 = −2(x − 1)

Simplify to Slope-Intercept (y = mx + b) form:

y − 6 = −2x + 2

y = −2x + 8

DONE!

The Big Exception

The previous method works nicely except for one particular case: a vertical line:

What is the equation of the line which passes through the point 2 3 and (

A vertical line's gradient is undefined (because we cannot divide by 0):

m = yA − yBxA − xB = 4 − 12 − 2 = 30 = undefined

But there is still a way of writing the equation: use x= instead of y=, like this:

x = 2

7270, 525, 526, 1165, 1166, 7291, 7292, 7300, 7301, 7302

What is an equation of the line that passes through the point (

Summary : The equation of the line that passes through (-2, 3) and is parallel to 2x + 3y = 6 is 2x + 3y - 5 = 0.

What is an equation of the line that passes through the point (

y - 3 = m(x+2 ) Or y = m(x+2) + 3 is the line that passes through (-2, 3) and there are infinitely many such lines.

What is the equation of the line which passes through the point 2 3 and (

What is the equation of the line that passes through (4, -1) and (-2, 3)? We have to find the equation of the line. Therefore, the equation of the line is 2x + 3y - 5 = 0.

What is the equation of straight line which is passes through the point 2 3 and equally intercept on both axes?

Thus, the equation of line cuts off equal intercepts on the coordinate axes and passes through the point ( 2 , 3 ) is x + y = 5 .