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Question Description Solutions for The H.C.F of two numbers, each having three digits, is 19 and their L.C.M. is 3553. The sum of the numbers will be:a)209b)323c)532d)435Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for UPSC. Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free. Here you can find the meaning of The H.C.F of two numbers, each having three digits, is 19 and their L.C.M. is 3553. The sum of the numbers will be:a)209b)323c)532d)435Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The H.C.F of two numbers, each having three digits, is 19 and their L.C.M. is 3553. The sum of the numbers will be:a)209b)323c)532d)435Correct answer is option 'C'. Can you explain this answer?, a detailed solution for The H.C.F of two numbers, each having three digits, is 19 and their L.C.M. is 3553. The sum of the numbers will be:a)209b)323c)532d)435Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of The H.C.F of two numbers, each having three digits, is 19 and their L.C.M. is 3553. The sum of the numbers will be:a)209b)323c)532d)435Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The H.C.F of two numbers, each having three digits, is 19 and their L.C.M. is 3553. The sum of the numbers will be:a)209b)323c)532d)435Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice UPSC tests.
Option 2 : 38 Given: The HCF of two 2-digit numbers is 19 and their sum is 152. Concept used: If P is the HCF of A and B then A = P × m B = P × n (Where m, and n are arbitrary positive integers and they are co-prime to each other) Calculation: Let the above-mentioned 2-digit numbers be 19a and 19b. (Here, a, and b are arbitrary positive integers and they are co-prime to each other)) According to the question, 19a + 19b = 152 ⇒ a + b = 8 Hence, the numbers are 2-digit, and the possible set of values of (a,b) are (2, 6), (3, 5), and (4, 4). Thus, with the hit and trial method, we can confirm that only (3, 5) satisfies to be a value of (a, b). Hence, their difference = 19a - 19b = 19 × 5 - 19 × 3 = 38 ∴ Their difference is 38. Given: The HCF of two 2-digit numbers is 19 and their sum is 152. Concept used: If P is the HCF of A and B then A = P × m B = P × n (Where m, and n are arbitrary positive integers and they are co-prime to each other) Calculation: Let the above-mentioned 2-digit numbers be 19a and 19b. (Here, a, and b are arbitrary positive integers and they are co-prime to each other)) According to the question, 19a + 19b = 152 ⇒ a + b = 8 Hence, the numbers are 2-digit, and the possible set of values of (a,b) are (2, 6), (3, 5), and (4, 4). Thus, with the hit and trial method, we can confirm that only (3, 5) satisfies to be a value of (a, b). Hence, their difference = 19a - 19b = 19 × 5 - 19 × 3 = 38 ∴ Their difference is 38. |
The hcf of two 2-digit numbers is 19 and their sum is 152. what is their difference?
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