Solution: The coordinates of the point P(x, y) which divides the line segment joining the points A(x₁, y₁) and B(x₂, y₂) internally in the ratio m₁: m₂ is given by the section formula. Let the points be A(4, - 1) and B(- 2, - 3). Let P (x₁, y₁) and Q (x₂, y₂) be the points of trisection of the line segment joining the given points. Then, AP = PC = CB By Section formula , P(x, y) = [(mx₂ + nx₁) / (m + n), (my₂ + ny₁) / (m + n)] ...... (1) Considering A(4, - 1) and B(- 2, - 3), by observation point P(x₁, y₁) divides AB internally in the ratio 1 : 2. Hence m : n = 1 : 2 By substituting the values in the Equation (1) x₁ = [1 × (- 2) + 2 × 4] / (1 + 2) x₁ = (- 2 + 8) / 3 = 2 y₁ = [1 × (- 3) + 2 × (- 1)] / (1 + 2) y₁ = (- 3 - 2) / (1 + 2) = - 5/3 Hence, P(x₁ , y₁) = (2, - 5/3) Now considering A(4, - 1) and B(- 2, - 3), by observation point C(x₂, y₂) divides AB internally in the ratio 2 : 1. Hence m : n = 2 : 1 By substituting the values in the Equation (1) x₂ = [2 × (- 2) + 1 × 4] / (2 + 1) = (- 4 + 4) / 3 = 0 y₂ = [2 × (- 3) + 1 × (- 1)] / (2 + 1) = (- 6 - 1) / 3 = - 7/3 Therefore, C(x₂ , y₂) = (0, - 7/3) Hence, the points of trisection are P(x₁ , y₁) = (2, - 5/3) and C (x₂ , y₂) = (0, - 7/3) ☛ Check: NCERT Solutions Class 10 Maths Chapter 7 Video Solution: Find the coordinates of the points of trisection of the line segment joining (4, - 1) and (- 2, - 3).NCERT Class 10 Maths Solutions Chapter 7 Exercise 7.2 Question 2 Summary: The coordinates of the points of trisection of the line segment joining (4, - 1) and (- 2, - 3) are (2, - 5/3) and (0, - 7/3). ☛ Related Questions:
|