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Answer : the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules. Explanation: The answer can be calculated using the formula Q = mCрΔT where Q is the amount of heat required in joules to raise the temperature. m is the mass of the sample in Kg. Cp is the specific heat of the sample in J/Kg°C. ΔT is the change in temperature required. Here, m = 49.5-gram = 0.0495 kg Cp = 4.18 J/Kg°C (for water) T₁ = 22°C ; T₂ = 66°C ΔT = 66 - 22 = 44 Substituting values in Q = mCрΔT Q = (0.0495)(4.18)(44) Q = 9.104 J
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Howard University
Jeffrey B. Chemistry 101 7 months, 3 weeks ago
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