In order to continue enjoying our site, we ask that you confirm your identity as a human. Thank you very much for your cooperation.
India's Super Teachers for all govt. exams Under One Roof
Concept: Entropy
\(S = \frac{{{\rm{Δ }}Q}}{T}\) Where S is entropy, Δ Q is heat exchanged and T is the temperature in Kelvin. Latent Heat
l = 80 calorie. Calculation: Given mass of ice = 10 gm Heat required to convert in water = m × l = 10 gm × 80 cal = 800 Cal Temperature T = 0°C = 273 K \(S = \frac{{{\rm{Δ }}Q}}{T}\) \(\implies S = \frac{800\ cal}{273K}\) ⇒ S = 2.93 cal/K So, the correct option is 2.93 cal/K India’s #1 Learning Platform Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes Trusted by 3.3 Crore+ Students |