What is the positive number which when increased by 17 is equal to 60 times reciprocal of the number?

What are you looking for? Let’s dig in quickly

Explanation

• Find a positive number which when increased by 17.

• Is equal to 60 times the reciprocal of the number.

• The number can be figure out in this way.

Let suppose the positive number is y.

60 times the reciprocal of the number

60 x 1/y

Positive number when increased by 17

y + 17 = 60 x 1/y ________ (i)

Through equation (i) we can easily find out the value of y (y = 3).

To Find

Number = ?

Solution

Let suppose

Number = y

According to the given condition

y + 17 = 1/y x 60

y(y + 17) = 60

y2 + 17y = 60

y2 + 17y – 60 = 0

y2 + 20y – 3y – 60 = 0

y(y + 20) – 3(y + 20) = 0

(y + 20)(y – 3) = 0

y + 20 = 0           &                y – 3 = 0

y = -20 (not possible)           &                y = 3 (possible)

Required Number = 3 answer

Conclusion

Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number. The number is 3 which is the required answer.

Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

No worries! We‘ve got your back. Try BYJU‘S free classes today!

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App