What is the smallest number by which 625 must be divided so that the quotient is a perfect cube 25 5 2 3?

Answered by Guest on 2018-01-20 04:51:20 | Votes 0 | #

Answer for this question is option 2

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What is the smallest positive integer by which 625 must be divided so [#permalink]

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What is the smallest positive integer by which 625 must be divided so that the quotient is a perfect cube?(A) 125 (B) 25(C) 5(D) 3

(E) 2

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Re: What is the smallest positive integer by which 625 must be divided so [#permalink]

Option: CPrime factorization of 625 is625 = 5 × 5 × 5 × 5As seen above the smallest prime factor is 5Here a perfect cube would be 5 x 5 x 5 = 125Therefore 5 is the smallest positive integer by which 625 must be divided to get a perfect cube as a quotient.

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Re: What is the smallest positive integer by which 625 must be divided so [#permalink]

Home » Aptitude » Simplification » Question

1. What is the smallest number by which 625 must be divided so that the quotient is a perfect cube ?

∴  625 = 5 × 5 × 5 × 5 = 53 × 5For the smallest cube number,625 should be divided 5,

625 ÷ 5 = 125 = 53

Correct Answer:

Description for Correct answer:

5 | 625 5 | 125 5 | 25 5 | 5 | 1\( \Large 625 = 5 \times 5 \times 5 \times 5 \)

Smallest number = 5

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