What mass of sodium chloride would be needed to produce a saturated solution of NaCl in 50 g of water at 313 K?

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Last updated at June 12, 2021 by

(a) At 313K, 

Mass of potassium nitrate needed to produce a saturated solution of potassium nitrate in 100g water = 62g

Mass of potassium nitrate needed to produce a saturated solution of potassium nitrate in 1g water = 62g/100g

Mass of potassium nitrate needed to produce a saturated solution of potassium nitrate in 1g water = 62gx50g/100g

          = 62g/2

           =31 g

(b) Solubility of solids in liquid decreases with decrease in temperature.

Room temperature is 298K while the saturated solution was formed at 253K. Hence, she will find crystals of potassium chloride when the solution cools down.

(c) Solubility is the maximum amount of solute which can be dissolved in 100 gm of Solvent at a particular temperature.

Hence the solubility of the following at 293K is

  • Potassium Nitrate - 32
  • Sodium Chloride - 36
  • Potassium Chloride - 35
  • Ammonium Chloride - 37

(d) From the above table we can see that the solubility of a salt is directly proportional to the temperature. 

As the temperature increases the solubility also increases. 

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Text Solution

Solution : (a) Mass of potassium chloride in 100 g of water in saturated solution = 46 g <br> Mass of potassium chloride in 50 g of water in saturated solution = `((46 g))/((100 g)) xx (50g) = 23 g` <br> (b) When the solution is cooled, the solubility of salt in water will decrease. This means that upon cooling, it will start separating from the solution in crystalline form.

Text Solution

Solution :  At `30^@ C`, 36 g of sodium chloride is dissolved in 100 g of water.<br>`therefore `Mass of sodium chloride that would be need for 100 g of water = 36 g <br> `therefore ` Mass of sodium chloride dissolved in 50 g of 100 g of water `=( 36 xx 50 )/( 100 )= 18 g `

Hey!

The solution is as follows :

Solubility of potassium nitrate at  313K = 62/100 100 g of water contains potassium nitrate = 62 g 50 g of water contains potassium nitrate = 62/100 X 50 = 31g

Thus, 31 g potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 g of water at 313 K.

Hope it helped to clear your delimma

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