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Guys, does anyone know the answer?
get what number should be subtracted from each of the numbers 18 24 28 from screen.
What number should be subtracted from each of the numbers 23, 30, 57 and 78 so that the remainders are in proportion?
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Question
What number should be subtracted from each of the numbers 23,30,57 and 78 so that the remainders are in proportion?
Medium Open in App Solution Verified by Toppr
Consider x be subtracted from each term
So, 23βx,30βx,57βx and 78βx are proportional
It can be written as
(23βx):(30βx)::(57βx):(78βx)
(30βx) (23βx) β = (78βx) (57βx) β
By cross multiplication
(23βx)(78βx)=(30βx)(57βx)
By further calculation
1794β23xβ78x+x 2 =1710β30xβ57x+x 2 βx 2 β101x+1794βx 2 +87xβ1710=0 So we get β14x+84=0 β14x=84 βx= 14 84 β =6
Therefore, 6 is the number to be subtracted from each of the numbers.
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What number should be subtracted from each of the numbers 4, 10 and 28 so that the remainder may be in continued proportion?
Answer (1 of 2): Answer is 1. Let x be the number to subtract from each number for continued proportion. We have (10-x)/(4-x) = (28-x)/(10-x) => (10-x)^2 = (28-x)(4-x) => 100β20x+x^2 = 112β32x+x^2 => 32x-20x = 112β100 => 12x = 12 or x = 1. The continued proportion is 3, 9, 27.
What number should be subtracted from each of the numbers 4, 10 and 28 so that the remainder may be in continued proportion?
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Suruti Ranjan Behera
M.Tech in Mechanical Engineering & Mechanical Machine Design, Kalinga Institute of Industrial Technology (KIIT) (Graduated 2019)Author has 179 answers and 647.5K answer views3y
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What should be subtracted from each of the numbers 54, 71, 75 , 99 so that the remainders may be proportional?
Let assume x is the number, if you subtracte from each of the numbers mentioned above in the question, so that the remainders may be proportion.
As per question,
54 - x , 71 - x , 75 - x , and 99 - x are in proportion.
(54 - x) / (71 - x) = (75 - x) / ( 99 - x)
(54 - x)( 99 - x) = (75 - x) (71 - x)
x^2 - 99x - 54x + 5346 = x^2 - 75x - 71x + 5325
(multiplying both side)
- 153x + 5346 = -146x + 5325(x^2 cancelled both side)
153x- 146x = 5346 - 5325
7x = 21 β΄ x = 3.
So, 3 should be subtracted from each of the numbers54,71,75,99 so that the remainders may be proportional.
Hope it's will help you.
Thanks for re Related questions
What number should be subtracted from each of the numbers 23,30,57 and 78 so that the remainders are in proportion? (A) 4 (B) 3 (C) 6 (D) 7?
What number must be subtracted from each of the numbers 18, 78, 19 and 83, so that the remainder will be in proportion?
In a class of 20 students in an examination in mathematics, 2 students scored 100 marks each, 3 got zero each, and the average of the rest was 40. What is the average for the whole class?
80 is subtracted from 30% of a number, the result is 50. What is the number?
How many terms are there in Arithmetic Progression 7, 10, 13,β¦43?
Atharva Dinkar
Studied at BITS Pilani, K. K. Birla Goa Campus (Graduated 2021)5y
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What number should be subtracted from each of the numbers 23,30,57 and 78 so that the remainders are in proportion? (A) 4 (B) 3 (C) 6 (D) 7?
The answer is (C) 6
Let the required number be βxβ. after subtracting x from the given numbers, we have 23-x, 30-x, 57-x, 78-x.
At this point, you can choose to be lazy and see which option fits, or solve it the βgoodβ way.
(23βx)/(30βx)=(57βx)/(78βx)
(23βx)/(30βx)=(57βx)/(78βx)
Transposing, we get x 2 β101x+1794= x 2 β87x+1710
x2β101x+1794=x2β87x+1710
14x=84 14x=84 x=6 x=6 S. S. Agarwal
Math Competition Problems, Most Viewed Writer - QuoraAuthor has 442 answers and 1.4M answer views3y
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When 9 is subtracted from a number and then divided by 2, the answer is 4. What is the number?
Ans. Let's assume the required number be X and X-9 be Y.
So equation should be,
First equation, X - 9 =Y
Second equation, Y / 2 = 4
By solving the second equation we get,
Y = 4Γ2 Y = 8
Now putting the value of Y in first equation, we get
X - 9 = Y
X = 8 +9 [putting Y = 8]
X = 17.
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Mahi Sharma
Student at Amity International School, NoidaAuthor has 57 answers and 187.8K answer views2y
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When 12 is subtracted from 3times a certain number and the result is divided by 4. The answer is 18. What is the number?
I am not very good at maths, but I think this is the correct answer.
Answer is 28. Explanation:
So, let us assume the number to be x.
For forming the equation:
Now, according to the question, if twelve is subtracted from three times the number, ie.
Three times the number will be 3x.
Subtract 12 from it, we get 3x-12.
Now, when we divide it from 4, ie.,
3x-12/4, we get the answer as 18.
So the equation is 3x-12/4=18.
Now, solving the equation:
We cross multiply.
So, the equation formed will be 3x-12=18*4
=) 3x-12=72 =) 3x=72+12 =) 3x=84 =) x= 84/3 =) x=28.
Therefore, the number is 28.
Hope it helps you. Upvote if
Rebecca Harvey
Author has 1.4K answers and 597.5K answer views1y
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What two numbers make 10 adding and 3 subtracting?
Presuming you don't need whole numbers, 3.5 and 6.5.
3.5 + 6.5 = 10 6.5 - 3.5 = 3
Do you need the method/workings?
I'm a little rusty, but the way I'd do this would e with algebra.
X + y = 10 X - y = 3
Add them together = x + x + y - y = 13
= 2x = 13
Therefore x = 13 Γ· 2 = 6.5
To calculate y, substitute 6.5 with x in a previous equation:
X + y = 10 6.5 + y = 10
Therefore y = 10 - 6.5 = 3.5
Dorota Zarzycka
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Which number should be subtracted from each of the numbers 11, 23 and 53 so that the resulting numbers would be in continued proportion?
3.
(11β3)/(23β3)=(23β3)/(53β3)
8/20=20/50
The way you arrive at it is as follows:
(11-x)/(23-x)=(23-x)/(53-x)
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What number should be subtracted from each of the numbers 23 30 57 and 78 so that the remainders are...
Free solutions for M L Aggarwal - Understanding ICSE Mathematics - Class 10 Chapter 7 - Ratio and Proportion Ratio and Proportion Exercise 7.2 question 7. These explanations are written by Lido teacher so that you easily understand even the most difficult concepts
ML Aggarwal Solutions Class 10 Mathematics Solutions for Ratio and Proportion Exercise 7.2 in Chapter 7 - Ratio and Proportion
Prev Question 7 Next
What number should be subtracted from each of the numbers 23, 30, 57, and 78 so that the remainders are in proportion?
Answer:
Consider x be subtracted from each term
23 β x, 30 β x, 57 β x and 78 β x are proportional
It can be written as
23 β x: 30 β x :: 57 β x: 78 β x
(23 β x)/ (30 β x) = (57 β x)/ (78 β x)
By cross multiplication
(23 β x) (78 β x) = (30 β x) (57 β x)
By further calculation
\begin{array}{l} 1794-23 x-78 x+x^{2}=1710-30 x-57 x+x^{2} \\ x^{2}-101 x+1794-x^{2}+87 x-1710=0 \end{array}
1794β23xβ78x+x 2 =1710β30xβ57x+x 2 x 2 β101x+1794βx 2 +87xβ1710=0 β So we get -14x + 84 = 0 14x = 84 x = 84/14 = 6
Therefore, 6 is the number to be subtracted from each of the numbers.
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