What weight of glucose should be added to 1700 gram of water at 20 degree Celsius to lower its Vapour pressure?

Text Solution

Answer : 1

Solution : Given, `P^(@) - P_(S) = 0.001 mm`, <br> `P^(@) = 17 mm, P_(S) = 16.999, m = 180`, <br> `M = 18, W = 1700, w = ?` <br> Now `(P^(@)-P_(S))/(P_(S)) = (w//m)/(W//M)` <br> `rArr (0.001)/(16.999) = (w xx 18)/(180 xx 1700) rArr w = 1 g`