What will be the masses of cane sugar and water required to prepare 250 g of 25% solution of cane sugar?

Answer

Hint: We know that mass percentage is one way to express concentration of a solution using the mass of solute and solution. Here, we have to use the formula of mass percentage, that is, ${\rm{Mass}}\% = \dfrac{{{\rm{Mass}}\,{\rm{of}}\,{\rm{solute}}}}{{{\rm{Mass}}\,{\rm{of}}\,{\rm{solution}}}} \times 100$.

Complete step by step answer:

Therefore, the mass of water in the solution is 187.5 g.

Note:

Text Solution

`187.5` grams, `62.5` grams`62.5` grams, `187.5` grams`162.5` grams, `87.5` gramsNone of these

Answer : B

Solution : Mass percent of sugar = `25` <br> we know that <br> Mass percentage `= ("Mass of solute")/("Mass of solution")xx100 ` <br> So, `25 = ("Mass of cane sugar")/(250)xx100` <br> or Mass of cane sugar =` (25xx250)/(100)= 62.5 ` grams. <br> Mass of water =` (250-62.5)= 187.5 `grams

Text Solution

Solution : Mass percent `=("Mass of solute")/("Mass of solution")xx100` <br> Mass percent =25, Mass of solution = 250 g <br> `:. 25 = ("Mass of can sugar")/((250 g))xx100` <br> `:.` Mass of cane sugar `= (25 xx(250 g))/(100)=62.5 ,` Mass of water `= 250-62.5=187.5g`.