Text Solution
3m5m6m8m/s
Solution : 6m <br> In the case of a plane mirror, the distance between the object and the mirror `(d_(1))` is same as the distance between the image and the mirror `(d_(2))`. <br> <img src="//doubtnut-static.s.llnwi.net/static/physics_images/NCERT_SCI_VII_C15_E01_020_S01.png" width="80%"> <br> Given, <br> Distance between the mirror and David.s image , `d_(2) = 4m` <br> Therefore, `d_(1) = d_(2) = 4m` <br> If David moves 1m towards the mirror, the `d_(1) = 4-1 = 3m` <br> Again, `d_(1) = d_(2) = 3m` <br> Therefore, the distance between David and his image is `d_(1) + d_(2) = 3 + 3 = 6m`.
David is observing his image in a plane mirror. The distance between the mirror and his image is 4 m. If he moves 1 m towards the mirror, then the distance between David and his image will be i 3 m ii 5 m iii 6 m iv 8 m
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