When asked of an estimation of population mean but population standard deviation is unknown brainly

The statistic used to estimate the mean of a population, μ, is the sample mean,

When asked of an estimation of population mean but population standard deviation is unknown brainly
.

When asked of an estimation of population mean but population standard deviation is unknown brainly

If X has a distribution with mean μ, and standard deviation σ, and is approximately normally distributed or n is large, then

When asked of an estimation of population mean but population standard deviation is unknown brainly
is approximately normally distributed with mean μ and standard error
When asked of an estimation of population mean but population standard deviation is unknown brainly
..

When σ Is Known

If the standard deviation, σ, is known, we can transform

When asked of an estimation of population mean but population standard deviation is unknown brainly
to an approximately standard normal variable, Z:

 

When asked of an estimation of population mean but population standard deviation is unknown brainly

Example:

From the previous example, μ=20, and σ=5. Suppose we draw a sample of size n=16 from this population and want to know how likely we are to see a sample average greater than 22, that is P(

When asked of an estimation of population mean but population standard deviation is unknown brainly
> 22)?

When asked of an estimation of population mean but population standard deviation is unknown brainly

So the probability that the sample mean will be >22 is the probability that Z is > 1.6 We use the Z table to determine this:

P( > 22) = P(Z > 1.6) = 0.0548.

When asked of an estimation of population mean but population standard deviation is unknown brainly
 

Exercise: Suppose we were to select a sample of size 49 in the example above instead of n=16. How will this affect the standard error of the mean? How do you think this will affect the probability that the sample mean will be >22? Use the Z table to determine the probability.

Answer

When asked of an estimation of population mean but population standard deviation is unknown brainly

When σ Is Unknown

If the standard deviation, σ, is unknown, we cannot transform

When asked of an estimation of population mean but population standard deviation is unknown brainly
to standard normal. However, we can estimate σ using the sample standard deviation, s, and transform
When asked of an estimation of population mean but population standard deviation is unknown brainly
to a variable with a similar distribution, the t distribution. There are actually many t distributions, indexed by degrees of freedom (df). As the degrees of freedom increase, the t distribution approaches the standard normal distribution.

 

When asked of an estimation of population mean but population standard deviation is unknown brainly

If X is approximately normally distributed, then

When asked of an estimation of population mean but population standard deviation is unknown brainly

has a t distribution with (n-1) degrees of freedom (df)

Using the t-table

Note: If n is large, then t is approximately normally distributed.

 

When asked of an estimation of population mean but population standard deviation is unknown brainly

When asked of an estimation of population mean but population standard deviation is unknown brainly
 

The z table gives detailed correspondences of P(Z>z) for values of z from 0 to 3, by .01 (0.00, 0.01, 0.02, 0.03,…2.99. 3.00). The (one-tailed) probabilities are inside the table, and the critical values of z are in the first column and top row.

The t-table is presented differently, with separate rows for each df, with columns representing the two-tailed probability, and with the critical value in the inside of the table.

The t-table also provides much less detail; all the information in the z-table is summarized in the last row of the t-table, indexed by df = ∞.

So, if we look at the last row for z=1.96 and follow up to the top row, we find that

 P(|Z| > 1.96) = 0.05

When asked of an estimation of population mean but population standard deviation is unknown brainly

Exercise: What is the critical value associated with a two-tailed probability of 0.01?

Answer

When asked of an estimation of population mean but population standard deviation is unknown brainly

Now, suppose that we want to know the probability that Z is more extreme than 2.00. The t-table gives us

P(|Z| > 1.96) = 0.05

And

P(|Z| > 2.326) = 0.02

So, all we can say is that P(|Z| > 2.00) is between 2% and 5%, probably closer to 5%! Using the z-table, we found that it was exactly 4.56%.

Example:

In the previous example we drew a sample of n=16 from a population with μ=20 and σ=5. We found that the probability that the sample mean is greater than 22 is P(

When asked of an estimation of population mean but population standard deviation is unknown brainly
> 22) = 0.0548. Suppose that is unknown and we need to use s to estimate it. We find that s = 4. Then we calculate t, which follows a t-distribution with df = (n-1) = 24.

When asked of an estimation of population mean but population standard deviation is unknown brainly
 

From the tables we see that the two-tailed probability is between 0.01 and 0.05.

P(|T| > 1.711) = 0.05

And

P(|T| > 2.064) = 0.01

When asked of an estimation of population mean but population standard deviation is unknown brainly

To obtain the one-tailed probability, divide the two-tailed probability by 2.

P(T > 1.711) = ½ P(|T| > 1.711) = ½(0.05) = 0.025

And

P(T > 2.064) = ½ P(|T| > 2.064) = ½(0.01) = 0.005

So the probability that the sample mean is greater than 22 is between 0.005 and 0.025 (or between 0.5% and 2.5%)

When asked of an estimation of population mean but population standard deviation is unknown brainly

Exercise: . If μ=15, s=6, and n=16, what is the probability that

When asked of an estimation of population mean but population standard deviation is unknown brainly
>18 ?

Answer

When asked of an estimation of population mean but population standard deviation is unknown brainly


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The t-distribution describes the standardized distances of sample means to the population mean when the population standard deviation is not known, and the observations come from a normally distributed population.

Is the t-distribution the same as the Student’s t-distribution?

Yes.

What’s the key difference between the t- and z-distributions?

The standard normal or z-distribution assumes that you know the population standard deviation. The t-distribution is based on the sample standard deviation.

The t-distribution is similar to a normal distribution. It has a precise mathematical definition. Instead of diving into complex math, let’s look at the useful properties of the t-distribution and why it is important in analyses.

  • Like the normal distribution, the t-distribution has a smooth shape.
  • Like the normal distribution, the t-distribution is symmetric. If you think about folding it in half at the mean, each side will be the same.
  • Like a standard normal distribution (or z-distribution), the t-distribution has a mean of zero.
  • The normal distribution assumes that the population standard deviation is known. The t-distribution does not make this assumption.
  • The t-distribution is defined by the degrees of freedom. These are related to the sample size.
  • The t-distribution is most useful for small sample sizes, when the population standard deviation is not known, or both.
  • As the sample size increases, the t-distribution becomes more similar to a normal distribution.

Consider the following graph comparing three t-distributions with a standard normal distribution:

Figure 1: Three t-distributions and a standard normal (z-) distribution.

All of the distributions have a smooth shape. All are symmetric. All have a mean of zero.

The shape of the t-distribution depends on the degrees of freedom. The curves with more degrees of freedom are taller and have thinner tails. All three t-distributions have “heavier tails” than the z-distribution.

You can see how the curves with more degrees of freedom are more like a z-distribution. Compare the pink curve with one degree of freedom to the green curve for the z-distribution. The t-distribution with one degree of freedom is shorter and has thicker tails than the z-distribution. Then compare the blue curve with 10 degrees of freedom to the green curve for the z-distribution. These two distributions are very similar.

A common rule of thumb is that for a sample size of at least 30, one can use the z-distribution in place of a t-distribution. Figure 2 below shows a t-distribution with 30 degrees of freedom and a z-distribution. The figure uses a dotted-line green curve for z, so that you can see both curves. This similarity is one reason why a z-distribution is used in statistical methods in place of a t-distribution when sample sizes are sufficiently large.

Figure 2: z-distribution and t-distribution with 30 degrees of freedom

When you perform a t-test, you check if your test statistic is a more extreme value than expected from the t-distribution.

For a two-tailed test, you look at both tails of the distribution. Figure 3 below shows the decision process for a two-tailed test. The curve is a t-distribution with 21 degrees of freedom. The value from the t-distribution with α = 0.05/2 = 0.025 is 2.080. For a two-tailed test, you reject the null hypothesis if the test statistic is larger than the absolute value of the reference value. If the test statistic value is either in the lower tail or in the upper tail, you reject the null hypothesis. If the test statistic is within the two reference lines, then you fail to reject the null hypothesis.

Figure 3: Decision process for a two-tailed test

For a one-tailed test, you look at only one tail of the distribution. For example, Figure 4 below shows the decision process for a one-tailed test. The curve is again a t-distribution with 21 degrees of freedom. For a one-tailed test, the value from the t-distribution with α = 0.05 is 1.721. You reject the null hypothesis if the test statistic is larger than the reference value. If the test statistic is below the reference line, then you fail to reject the null hypothesis.

Figure 4: Decision process for a one-tailed test

Most people use software to perform the calculations needed for t-tests. But many statistics books still show t-tables, so understanding how to use a table might be helpful. The steps below describe how to use a typical t-table.

  1. Identify if the table is for two-tailed or one-tailed tests. Then, decide if you have a one-tailed or a two-tailed test. The columns for a t-table identify different alpha levels.
    If you have a table for a one-tailed test, you can still use it for a two-tailed test. If you set α = 0.05 for your two-tailed test and have only a one-tailed table, then use the column for α = 0.025.
  2. Identify the degrees of freedom for your data. The rows of a t-table correspond to different degrees of freedom. Most tables go up to 30 degrees of freedom and then stop. The tables assume people will use a z-distribution for larger sample sizes.
  3. Find the cell in the table at the intersection of your α level and degrees of freedom. This is the t-distribution value. Compare your statistic to the t-distribution value and make the appropriate conclusion.