When object is placed at a distance of 50 cm from a concave lens of focal length 20 cm find the position nature and height of the image?

Get the answer to your homework problem.

Try Numerade free for 7 days

In order to continue enjoying our site, we ask that you confirm your identity as a human. Thank you very much for your cooperation.

Text Solution

Solution : First of all we find out the position of the image which is given by the image distance v. <br> Here, Object distance, u`=-50` cm (It is to the left of lens) <br> Image distance, v=? (To be calculated) <br> Focal length, f`=-20cm` (It is concave lens) <br> Putting these values in the lens formula: <br> `1/v-1/u=1/f` <br> we get, `1/v-(1/-50)=1/(-20)` <br> or `1/v+1/50=-1/20` <br> or `1/v=-1/20-1/50` <br> or `1/v=(-5-2)/(100)` <br> or `1/v=-7/100` <br> or `v=-100/7` <br> So, Image distance, `v=-14.3` cm <br> Thus, the image is formed at a distance of 14.3cm from the concave lens. The minus sign for image distance shows that the image is formed on the left side of the concave lens. We know that a concave lens always forms a virtul and erect image, so the nature of image is virtual and erect.

Uh-Oh! That’s all you get for now.

We would love to personalise your learning journey. Sign Up to explore more.

Sign Up or Login

Skip for now

Uh-Oh! That’s all you get for now.

We would love to personalise your learning journey. Sign Up to explore more.

Sign Up or Login

Skip for now