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Question 14 Real Numbers Exercise 1B Next Answer: Prime factors of 4, 7 and 13 4 = 2x2 7 and 13 are prime numbers. LCM ( 4, 7, 13) = 364 We know that, the largest 4 digit number is 9999 Step 1: Divide 9999 by 364, we get 9999/364 = 171 Step 2: Subtract 171 from 9999 9999 - 171 = 9828 Step 3: Add 3 to 9828 9828 + 3 = 9831 Therefore 9831 is the number. Was This helpful? Therefore, Greatest number of 4-digit which when divided by 3 , 5 , 7 , 9 and leaves remainder 1 , 3 , 5 , 7 respectively = 9765 - 2 = 9763 ( Ans ) Q. View complete answer on byjus.com Therefore 9831 is the number. Q. View complete answer on byjus.com What is the largest 4 digit number divisible by 19?Detailed Solution. ∴ 9994 is divisible by 19.View complete answer on testbook.com Detailed Solution∴ The highest four-digit number is 9998. View complete answer on testbook.com What is the greatest number smaller than 5000 which when divided by 5/6 and 7 respectively leaves remainder of 4/5 and 6?Therefore the correct answer is 423.View complete answer on testbook.com What is the greatest number of 3 digits which when divided by 6 9 and 12 leaves a remainder of 3 in each case?Here, we have to find the greatest 3-digit number which when divided by 6, 9 and 12 leaves a remainder 3 in each case. So, 972 is the greatest 3-digit number which is divisible by 36. ∵ It is given that in each case remainder is 3. Hence, option C is the correct answer.View complete answer on testbook.com What is the greatest 5 digit number which when divided by 6 7 8 and 12 leaves remainder 4 in each case?The greatest number divisible by 6, 7, 8, and 12. Therefore, the number has to be of form 168 x + 4, where x is an integer. So, 99999 - 39 = 99960 which is divisible by 168. ∴ The correct answer is 99964.View complete answer on testbook.com What is the largest number of 4 digits which divided by 6 9 12 15 18 leaves 1 as remainder in each case?9900 is divisible by each of 6, 9, 12, 15 and 18.View complete answer on selfstudy365.com What is the largest number of 4 digit which when divided by 7 12 15 20 leaves remainder 4 9 12 and 17 respectively?Now adding reminder 1 will get Largest 4 digit number will be 9792+1 = 9793.View complete answer on toppr.com Answer: The Largest number of four digits is 9999.by dividing 9999 to 612 get 207 as remainder. So, the greatest number of 4 digits divisible by any numbers from 6, 9, 12 or 17 = (9999-207) = 9792.View complete answer on brainly.in What are the largest 4 digit and smallest 3 digit numbers divisible by 6 15 21 & 24?Expert-verified answerThe largest 4 digit number is 9240 and smallest 3 digit number is 840. Step-by-step explanation: To find : What are the largest 4 digit and smallest 3 digit numbers divisible by 6,15,21 & 24 ? The smallest number in 3 digits, divisible by 6, 15, 21 and 24 is LCM. View complete answer on brainly.in What is the smallest 4 digit number divisible by 19?1007 is the least four digit no which is directly divided by 19 by 53 times .View complete answer on brainly.in Which of the following is the greatest 4 digit number which is divisible by 12 15 and 30?∴ The largest four-digit number exactly divisible by 12, 15, 20, and 35 is 9660.View complete answer on testbook.com So 9997. So it is quite clear that if you divide 9997 x 11 it would leave. Remanded nine.View complete answer on numerade.com What is the largest number smaller than 300 which when divided by both 4 and 7 gives a remainder of 3?Hence, the required numbers between 10 and 300, which when divided by 4 leave a remainder 3 are 73.View complete answer on toppr.com What will be the highest three digit number which when divided by 3 7 and 21 leaves remainder 2?Solution: The highest 3-digit number that is divisible by 3, 7, 21, and leaves the remainder as 2 is 989. We know that for a number to be divisible by the given three numbers, it has to be divisible by its LCM.View complete answer on brainly.in Which is the largest 3 Digitnumber that leaves Aremainder 1 when divided by3 4 and 5?∴The required answer is 301.View complete answer on brainly.in Solution(By Examveda Team)∴ 9960 is the largest four digit number which is completely divided by the given numbers. View complete answer on examveda.com What is the largest four digit number which when divided by 12 15 21 leaves remainder 7 each case?Detailed SolutionTo find the largest 4 digit number which, when divided by 12, 15 and 21, leaves remainder 7, we have to divide the 9999 by 420 and add 7 after subtracting the remainder from 9999. When we divide the 9999 by 420, the remainder is 339. View complete answer on testbook.com What is the least number of 4 digits which when divided by 6 9 and 12 leaves a remainder of 3 in each case?Expert-verified answerSince number leaves remainder as 3. = 1011. Thus, the least 4-digit number = 1011. Hope it helps! View complete answer on brainly.in What is the greatest 4 digit number which is exactly divisible by 12 and 15 and 14?Required number = 9999-279 = 9720.View complete answer on doubtnut.com To Find the greatest four digit number divisible by 72: The greatest four digit number is 9999. 9999 when divided by 72 is 138.875 ( 138.875 is not an integer, thus 9999 is not divisible by 72. ) The greatest four digit number divided by 72would be = 72*138=9936.View complete answer on byjus.com Which of the following is greatest 5 digit number which when divided by 3 6 8 and 11?Greatest number of 5 digits =99999. L.C.M of 3,6,8 and 11.View complete answer on brainly.in What is the greatest number of 5 digit which when divided by 3 5 8 and 12 leaves a remainder 2 in each case?Correct Option: D99960 is the greatest five digit number divisible by the given divisors. In order to get 2 as remainder in each case we will simply add 2 to 99960. View complete answer on interviewmania.com What is the least multiple of 13 which when divided by 3 4 5 8 and 10 leaves remainder 2 in each case?The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is : - GKToday. LCM of 4, 5, 6, 7 and 8 = 840.View complete answer on gktoday.in Find the largest four digits number which when divided by 4, 7 and 13 leaves a remainder of 3 in each case. Open in App 23
We know one solution $x = 23.\,$ If $x'$ is another solution then $\,x'= 5+6j,\ x= 5+6k\,$ so $\, x'-x = 6(j-k)\,$ is a multiple of $6$. Similarly $\,x'-x\,$ is a multiple of $5$. Thus $\,x'-x\,$ is a multiple of their lcm $= 30.\,$ Conversely if $\,x'-x=30n\,$ then $x',x$ have equal remainders $x$ mod $5$ and $6$. So the solutions are precisely integers of form $\,23+30n$. The largest multiple of $30$ below $1000$ is clearly $990$ and adding $23$ to that is too big, so we need to subtract $30$ then add $23$, yielding $983$. |
Which is the largest three digit number that leaves a remainder of 1 when divided by 3/4 and 5?
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