How to print an integer in C++

How to print an integer in C language? A user inputs an integer, and we print it. Input is done using scanf function, and the number is printed on screen using printf.

C program to print an int (integer)

#include <stdio.h>

 int main()
{
  int a;

   printf("Enter an integer\n");
  scanf("%d", &a);

   printf("The integer is: %d\n", a);

   return 0;
}

Output of the program:

C program to print first hundred positive integers [1, 100] using a for loop:

#include <stdio.h>

int main()
{
  int c;

  for (c = 1; c <= 100; c++)
    printf("%d ", c);

  return 0;
}

In C language, we have data types for different types of data, for integers, it's int, for characters it's char, for floating-point data, it's float, and so on. For large integers, you can use long or long long data type. To store integers that are greater than (2^18-1), which is the range of long long data type, you may use strings. In the below program, we store an integer in a string and display it.

C program to store an integer in a string

#include <stdio.h>

int main ()
{
   char n[1000];

      printf("Input an integer\n");
   scanf("%s", n);

      printf("%s", n);

   return 0;
}

Output of program:

Input an integer
12345678909876543210123456789
12345678909876543210123456789

An advantage of using a string is that we can store huge integers, but we can't perform arithmetic operations directly; for this, you can create functions. C programming language does not have a built-in data type for such numbers.