Today Wednesday, November 23, 2022 is ... Show
Day 327Day of the year is a number between 1 and 365 (in 2022), January 1 is day 1. This page uses the ISO8601 ordinal date format. There is also another lessused format: the 'ISO day of year' numbers, this is a number between 1 and 371, day 1 of the year is Monday of the first ISO week (where the first Thursday of the new year is in week 1). Lists of day numbers by year: 2021  2022  2023  2024 ... Programming routinesMicrosoft ExcelCalculate today's daynumber, starting from the day before Jan 1, so that Jan 1 is day 1. =TODAY()DATE(YEAR(TODAY()),1,0) or, for any date entered in cell A1, calculate the corresponding daynumber in that date’s year: =A1DATE(YEAR(A1),1,0) Google Docs Spreadsheet=DATEDIF(CONCAT("11";year(now()));today();"D")+1 Calculates the difference between Jan 1 and today (=days past) then add 1 for today's daynumber. (Your date format (11year) may be different) LibreOffice Calc:=ROUNDDOWN(DAYS(NOW(),DATE(YEAR(NOW()),1,1))) + 1 PHP$dayNumber = date("z") + 1; You can use an epoch to find other day numbers: date("z", epoch) + 1 date("z") starts counting from 0 (0 through 365)! Pythonfrom datetime import datetime day_of_year = datetime.now().timetuple().tm_yday PERLuse Time::Piece; my $day_of_year = localtime>yday + 1; # ... or ... my $day_of_year = (localtime)[7] +1; # ... or (if you really want to use POSIX) ... use POSIX; my $day_of_year = POSIX::strftime("%j", time); Replace time with other epochs for other days. MySQLSELECT DAYOFYEAR(NOW()) Day number between 1 and 366. Replace now() with other dates eg.: SELECT DAYOFYEAR('20220220'); Oracleselect to_char(sysdate, 'DDD') from dual select to_char(to_date('20220220','YYYYMMDD'), 'DDD') from dual Delphiusing DateUtils, SysUtils; DayOfTheYear(Date); Microsoft AccessDatePart("y", Now()) Visual Basic (VB.NET)Dim dayOfYear As Integer = DateTime.Now.DayOfYear JavaScriptvar today = new Date(); Math.ceil((today  new Date(today.getFullYear(),0,1)) / 86400000); Or add a 'Day of Year' method to the date object: Date.prototype.getDOY = function() { var onejan = new Date(this.getFullYear(),0,1); return Math.ceil((this  onejan) / 86400000); } var today = new Date(); var daynum = today.getDOY(); JavaLocalDate.now().getDayOfYear(); Unix/Linuxdate +%j ColdFusion#dayofyear(now())# Objective Cint currentDay; dateFormatter = [[NSDateFormatter alloc] init]; [dateFormatter setDateFormat:@"D"]; date = [NSDate date]; currentDay = [[dateFormatter stringFromDate:date] intValue]; C++Read the comment below by Mmars. C#int iDayOfYear = System.DateTime.UtcNow.DayOfYear; Rformat(Sys.Date(), "%j") Rubytime = Time.new puts time.yday Powershell$DayOfYear = (GetDate).DayofYear WriteHost $DayOfYear LiveCodeon mouseUp put "January 1," && the last word of the long date into firstDayofYear append current year convert firstDayofYear to seconds  from Jan 1, 1970 to first day of this year put the long date into currentDay convert currentDay to seconds  from Jan 1, 1970 GMT to today put currentDay  firstDayofYear into totalSeconds answer the round of (totalSeconds / (60*60*24)) + 1 display total days in dialog box end mouseUp Or: on mouseUp answer DayOfYear() end mouseUp function DayOfYear put the short date into currentDate convert currentDate to dateItems list of date elements separated by commas put item 1 of currentDate into year put item 2 of currentDate into month put item 3 of currentDate into day put floor (275 * month / 9) into N1 put floor ( (month + 9) / 12) into N2 put (1 + floor ( (year  4 * floor (year / 4) + 2) / 3) ) into N3 put N1  (N2 * N3) + day  30 into N return N end DayOfYear function floor pNumber  LiveCode has no builtin floor() function put Round (pNumber) into theInteger if theInteger > pNumber then put theInteger  1 into theInteger end if return theInteger end floor TSQL (TransactSQL)SELECT DATEPART(DAYOFYEAR, SYSDATETIME()) or SELECT datediff(day,CAST(datepart(year,getdate()) AS CHAR(4)) + '0101',getdate()+1) AS number_of_today Go (golang)day := time.Now().YearDay() MatlabdayNumber = todaydatenum(['1Jan' year(today)])+1 PowerbuilderRead the comment below by Danny Cruz. What number out of 365 days is today?This year has 365 days. Today is Nov 22, 2022 and current day number is 326.
What day of year is it out of 365?Day 326. Day of the year is a number between 1 and 365 (in 2022), January 1 is day 1. After today 39 days are remaining in this year.
What day of 2022 is today?The year 2022 has 365 days. Today (day 324, Sunday, November 20th) is highlighted. 'Percent of year' shows the percentage the year is complete at midnight (start of the day). Week number according to ISO8601.
