Today Wednesday, November 23, 2022 is ...
Day 327
Day of the year is a number between 1 and 365 (in 2022), January 1 is day 1.
After today 38 days are remaining in this year.
This page uses the ISO-8601 ordinal date format.
There is also another less-used format: the 'ISO day of year' numbers, this is a number between 1 and 371, day 1 of the year is Monday of the first ISO week (where the first Thursday of the new year is in week 1).
Lists of day numbers by year: 2021 - 2022 - 2023 - 2024 ...
Programming routines
Microsoft Excel
Calculate today's day-number, starting from the day before Jan 1, so that Jan 1 is day 1.
=TODAY()-DATE(YEAR(TODAY()),1,0) or, for any date entered in cell A1, calculate the corresponding day-number in that date’s year: =A1-DATE(YEAR(A1),1,0)Google Docs Spreadsheet
=DATEDIF(CONCAT("1-1-";year(now()));today();"D")+1Calculates the difference between Jan 1 and today (=days past) then add 1 for today's daynumber. (Your date format (1-1-year) may be different)
LibreOffice Calc:
=ROUNDDOWN(DAYS(NOW(),DATE(YEAR(NOW()),1,1))) + 1PHP
$dayNumber = date("z") + 1;You can use an epoch to find other day numbers:
date("z", epoch) + 1date("z") starts counting from 0 (0 through 365)!
Python
from datetime import datetime day_of_year = datetime.now().timetuple().tm_ydayPERL
use Time::Piece; my $day_of_year = localtime->yday + 1; # ... or ... my $day_of_year = (localtime)[7] +1; # ... or (if you really want to use POSIX) ... use POSIX; my $day_of_year = POSIX::strftime("%j", time);Replace time with other epochs for other days.
MySQL
SELECT DAYOFYEAR(NOW())Day number between 1 and 366. Replace now() with other dates eg.:
SELECT DAYOFYEAR('2022-02-20');Oracle
select to_char(sysdate, 'DDD') from dual select to_char(to_date('2022-02-20','YYYY-MM-DD'), 'DDD') from dualDelphi
using DateUtils, SysUtils; DayOfTheYear(Date);Microsoft Access
DatePart("y", Now())Visual Basic (VB.NET)
Dim dayOfYear As Integer = DateTime.Now.DayOfYearJavaScript
var today = new Date(); Math.ceil((today - new Date(today.getFullYear(),0,1)) / 86400000);Or add a 'Day of Year' method to the date object:
Date.prototype.getDOY = function() { var onejan = new Date(this.getFullYear(),0,1); return Math.ceil((this - onejan) / 86400000); } var today = new Date(); var daynum = today.getDOY();Java
LocalDate.now().getDayOfYear();Unix/Linux
date +%jColdFusion
#dayofyear(now())#Objective C
int currentDay; dateFormatter = [[NSDateFormatter alloc] init]; [dateFormatter setDateFormat:@"D"]; date = [NSDate date]; currentDay = [[dateFormatter stringFromDate:date] intValue];C++
Read the comment below by Mmars.
C#
int iDayOfYear = System.DateTime.UtcNow.DayOfYear;R
format(Sys.Date(), "%j")Ruby
time = Time.new puts time.ydayPowershell
$DayOfYear = (Get-Date).DayofYear Write-Host $DayOfYearLiveCode
on mouseUp put "January 1," && the last word of the long date into firstDayofYear --append current year convert firstDayofYear to seconds -- from Jan 1, 1970 to first day of this year put the long date into currentDay convert currentDay to seconds -- from Jan 1, 1970 GMT to today put currentDay - firstDayofYear into totalSeconds answer the round of (totalSeconds / (60*60*24)) + 1 --display total days in dialog box end mouseUpOr:
T-SQL (Transact-SQL)
SELECT DATEPART(DAYOFYEAR, SYSDATETIME())or
SELECT datediff(day,CAST(datepart(year,getdate()) AS CHAR(4)) + '-01-01',getdate()+1) AS number_of_todayGo (golang)
day := time.Now().YearDay()Matlab
dayNumber = today-datenum(['1-Jan-' year(today)])+1Powerbuilder
Read the comment below by Danny Cruz.
Thanks to all the developers who contributed to this page! (read comments below)