The wavelength of first line in the Balmer Series is 'whatever(in nm)' . Calculate the wavelength of the second line and the 'limiting line' in the Balmer Series.
I found this question in an ancient question paper in the library.
Now, I have solved the first part by calculating the atomic number from the first relation and then applying it while calculating the wavelengths of the second line in the Balmer series which must mean the line after Balmer (which is paschen). But for the second part 'what is limiting line', and that's exactly what my question is. Also since the given wavelength is in 'nanometer' what whould be the unit of energy if found.
I certainly don't need any solution for the above noted question( from the question paper), so this question cannot be declared as an 'homework question' due to some weird rules, (ofcourse they are meant for a mass good, but the tag name 'homework' hurts, anyway don't want that to be a topic of discussion here, but please consider it.)
Find the wavelength of the limiting line in the Lyman series of the hydrogen spectrum? R =1.097 × 10 2 nm 1A. 94.21 nmB. 911.6 nmC. 933.6 nmD. 91.16 nm
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