What is the equation of the plane through the point (1, 4 2) and parallel to the plane 2x y 3z 7

Answer:

Any plane parallel to 2x – y + 3z + 7 = 0 is shown as 2x – y + 3z + d = 0.

It passes through the point (1, 4, -2)

The equation of the plane is 2x – y + 3z + 8 = 0.

Text Solution

`2x-y+3z=8``2x-y+3z+8=0``2x-y+3z=4`none of these

Answer : B

Solution : Let the equation of a plane parallel to the plane `-2x+y-3z=7` be <br> `-2x+y-3z+k=0`……………i <br> This passes through (1,4,-2) <br> `:.(-2)(1)+4-3(-2)+k=0=k=-8` <br> Putting `k=-8` in i we obtain <br> `-2x+y-3z-8=0implies2x-y+3z+8=0`