We will discuss the definition of ellipse and how to find the equation of the ellipse whose focus, directrix and eccentricity are given. An ellipse is the locus of a point P moves on this plane in such a way that its distance from the fixed point S always bears a constant ratio to its perpendicular distance from the fixed line L and if this ratio is less than unity. An ellipse is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point (called focus) in the same plane to its distance from a fixed straight line (called directrix) is always constant which is always less than unity. The constant ratio usually denoted by e (0 < e < 1) and is known as the eccentricity of the ellipse. If S is the focus, ZZ' is the directrix and P is any point on the
ellipse, then by definition \(\frac{SP}{PM}\) = e ⇒ SP = e ∙ PM The fixed point S is called a Focus and the fixed straight line L the corresponding Directrix and the constant ratio is called the Eccentricity of the ellipse. Solved example to find the equation of the ellipse whose focus, directrix and eccentricity are given: Determine the equation of the ellipse whose focus is at (-1, 0), directrix is 4x + 3y + 1 = 0 and eccentricity is equal to \(\frac{1}{√5}\). Solution: Let S (-1, 0) be the focus and ZZ' be the directrix. Let P (x, y) be any point on the ellipse and PM be perpendicular from P on the directrix. Then by definition SP = e.PM where e = \(\frac{1}{√5}\). ⇒ SP\(^{2}\) = e\(^{2}\) PM\(^{2}\) ⇒ (x + 1)\(^{2}\) + (y - 0)\(^{2}\) = \((\frac{1}{\sqrt{5}})^{2}[\frac{4x + 3y + 1}{\sqrt{4^{2} + 3^{2}}}]\) ⇒ (x + 1)\(^{2}\) + y\(^{2}\) = \(\frac{1}{25}\)\(\frac{4x + 3y + 1}{5}\) ⇒ x\(^{2}\) + 2x + 1 + y\(^{2}\) = \(\frac{4x + 3y + 1}{125}\) ⇒ 125x\(^{2}\) + 125y\(^{2}\) + 250x + 125 = 0, which is the required equation of the ellipse. ● The Ellipse 11 and 12 Grade Math From Definition of Ellipse to HOME PAGE
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Fill in the blanks. The locus of a point in the plane that moves such that its distance from a fixed point (focus) is in a constant ratio to its distance from a fixed line (directrix) is a _______. simplify each. assume that none of the variables are zero. 1. Provide the conclusion for each statement: a) 2|4 and 2|24, therefore b) sla + b and sld + e, therefore Given: ℎ() = + 2 + 3; ℎ(6)a) 11b) -11c) 20d) -20 (×+3)(×+4) = 0 quadratic equation Pa answer po sa math given f (x)=x2-4*+4 find the range of each rational function PAGE:.. DATE:.. Taksdang Aralin Isalat ang sagot sa notebook 3 Isulat ang labing isa isa sa 2 3 sa Ma Given: = 3 − 2, what is (−2)? a) 1 b) 2 c) -1 d) -2 factor each completelya. a²-22a+121GCF=FF=b. 9a²+24a+16GCF=FF= c. a²-2a-24GCF=FF=d. a²+3x-10GCF=FF=pls pa help
Related Pages The following diagrams give the locus of a point that satisfy some conditions. Scroll down the page for more examples and solutions. When a point moves in a plane according to some given conditions the path along which it moves is called a locus. (Plural of locus is loci.). CONDITION 1: A point P moves such that it is always m units from the point Q. Locus formed: A circle with center Q and radius m. Example: Solution: CONDITION 2: A point P moves such that it is equidistant form two fixed points X and Y. Locus formed: A perpendicular bisector of the line XY. Example: Solution: CONDITION 3: A point P moves so that it is always m units from a straight line AB. Locus formed: A pair of parallel lines m units from AB. Example: Solution: CONDITION 4: A point P moves so that it is always equidistant from two intersecting lines AB and CD. Locus formed: Angle bisectors of angles between lines AB and CD. Example: Example: Five Fundamental Locus Theorems And How To Use Them Locus Theorem 1: The locus of points at a fixed distance, d, from the point, P is a circle with the given point P as its center and d as its radius. Locus Theorem 2: The locus of the points at a fixed distance, d, from a line, l, is a pair of parallel lines d distance from l and on either side of l. Locus Theorem 3: The locus of points equidistant from two points, P and Q, is the perpendicular bisector of the line segment determined by the two points. Locus Theorem 4: The locus of points equidistant from two parallel lines, l1 and l2, is a line parallel to both l1 and l2 and midway between them. Locus Theorem 5: The locus of points equidistant from two intersecting lines, l1 and l2, is a pair of bisectors that bisect the angles formed by l1 and l2. Example 1: Example 2: Example 3:
Five Rules Of Locus Theorem Using Real World Examples Locus is a set of points that satisfy a given condition. There are five fundamental locus rules. Rule 1: Given a point, the locus of points is a circle. Rule 2: Given two points, the locus of points is a straight line midway between the two points. Rule 3: Given a straight line, the locus of points is two parallel lines. Rule 4: Given two parallel lines, the locus of points is a line midway between the two parallel lines. Rule 5: Given two intersecting lines, the locus of points is a pair of lines that cut the intersecting lines in half.
Intersection Of Two LociSometimes you may be required to determine the locus of a point that satisfies two or more conditions. We could do this by constructing the locus for each of the conditions and then determine where the two loci intersect. Example: Solution: The points of intersections are indicated by points X and Y. It means that the locus consists of the two points X and Y. Example: Solution: Note: A common mistake is to identify only one point when there could be another point which could be found by extending the construction lines or arcs; as in the above examples. GCSE Maths Exam Questions - Loci, Locus And Intersecting Loci Examples:
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